What is the integral from 0 to pi of cos(x)sin^2(x) ?

The integral from 0 to pi of cos(x)sin^2(x) is 0

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integral from 0 to pi of cos(x)sin^2(x)

\int_{0}^{π} cos (x) sin^{2} (x) d x

0

Solution steps

\int_{0}^{π} cos (x) sin^{2} (x) d x

Compute the indefinite integral:

\int cos (x) sin^{2} (x) d x = \frac{sin ^{3} ( x )}{3} + C

Compute the boundaries:

\int_{0}^{π} cos (x) sin^{2} (x) d x = 0 - 0

= 0 - 0

Simplify

= 0

\int_{- 1}^{1} x sin (π x) d x

\int \frac{2}{u} d u

y^{^{''}} - 12 y^{^{'}} + 52 y = 0

\int_{0}^{1} (1 - x)^{9} d x

f (x) = 7 x + 9

What is the integral from 0 to pi of cos(x)sin^2(x) ?
The integral from 0 to pi of cos(x)sin^2(x) is 0