What is the derivative of \sqrt[4]{t}-4e^t ?

The derivative of \sqrt[4]{t}-4e^t is 1/(4t^{3/4)}-4e^t

What is the first derivative of \sqrt[4]{t}-4e^t ?

The first derivative of \sqrt[4]{t}-4e^t is 1/(4t^{3/4)}-4e^t

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derivative of

4 t - 4 e^{t}

\frac{1}{4 t ^{\frac{3}{4}}} - 4 e^{t}

Solution steps

\frac{d}{d t} (4 t - 4 e^{t})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (4 t) - \frac{d}{d t} (4 e^{t})

\frac{d}{d t} (4 t) = \frac{1}{4 t ^{\frac{3}{4}}}

\frac{d}{d t} (4 e^{t}) = 4 e^{t}

= \frac{1}{4 t ^{\frac{3}{4}}} - 4 e^{t}

\frac{\partial}{\partial x} (z sin^{2} (x))

f (x) = cos (6 x) \cdot 6

\frac{d}{d x} (2 x^{3} + \frac{1}{24 x})

x \to 2 lim (\frac{1 - x}{x - 2})

\frac{- 2 ( x - 9 )}{x ^{4}}

What is the derivative of \sqrt[4]{t}-4e^t ?
The derivative of \sqrt[4]{t}-4e^t is 1/(4t^{3/4)}-4e^t
What is the first derivative of \sqrt[4]{t}-4e^t ?
The first derivative of \sqrt[4]{t}-4e^t is 1/(4t^{3/4)}-4e^t