What is the integral of sqrt(w+5) ?

The integral of sqrt(w+5) is 2/3 (w+5)^{3/2}+C

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integral of sqrt(w+5)

\int w + 5 d w

\frac{2}{3} (w + 5)^{\frac{3}{2}} + C

Solution steps

\int w + 5 d w

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = w + 5

= \frac{2}{3} (w + 5)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{3} (w + 5)^{\frac{3}{2}} + C

\frac{\partial}{\partial y} (\frac{z}{x ^{2} + y ^{2} + z ^{2}})

\int_{0}^{9} 100 - 10 t d t

\frac{d}{d x} (x^{3} + 6 x)

x \to - 5 lim (\frac{3}{4})

(3 x^{2} - 5 x) e^{x}

What is the integral of sqrt(w+5) ?
The integral of sqrt(w+5) is 2/3 (w+5)^{3/2}+C