What is the derivative of x^3+6x ?

The derivative of x^3+6x is 3x^2+6

What is the first derivative of x^3+6x ?

The first derivative of x^3+6x is 3x^2+6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{3} + 6 x)

3 x^{2} + 6

Solution steps

\frac{d}{d x} (x^{3} + 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (6 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6 x) = 6

= 3 x^{2} + 6

x \to - 5 lim (\frac{3}{4})

(3 x^{2} - 5 x) e^{x}

x \to 0 + lim (- \frac{1}{x})

\frac{d y}{d t} = - y^{2}, y (0) = \frac{1}{2}

\int e^{5 x} \cdot 3 e^{5 x} + 2 d x

What is the derivative of x^3+6x ?
The derivative of x^3+6x is 3x^2+6
What is the first derivative of x^3+6x ?
The first derivative of x^3+6x is 3x^2+6