What is the x*y^2*y'(x)=y+1,y(5e^2)=3 ?

The x*y^2*y'(x)=y+1,y(5e^2)=3 is 4

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xy^2y'(x)=y+1,y(5e^2)=3

x \cdot y^{2} \cdot y^{'} (x) = y + 1, y (5 e^{2}) = 3

4

Solution steps

Find

y + 1

given

y (5 e^{2}) = 3

y + 1 = y + 1

Constant function results in a constant

y (5 e^{2}) = 3

3 + 1 = 4

= 4

x \to 2 - lim (2 x^{2} + 7)

f (x) = x^{2}, (\frac{5}{3}, \frac{25}{9})

\int t e^{(4 - s) t} d t

\int 4^{2 x} d x

\frac{2}{s ^{3} + 3 s ^{2} - 4}