What is the first derivative of 3-x ?

The first derivative of 3-x is -1

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derivative of 3-x

\frac{d}{d x} (3 - x)

- 1

Solution steps

\frac{d}{d x} (3 - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3) - \frac{d x}{d x}

\frac{d}{d x} (3) = 0

\frac{d x}{d x} = 1

= 0 - 1

Simplify

= - 1

\int \frac{1}{8 + x ^{2}} d x

\int_{5}^{- 5} \frac{1}{∣ x ∣ ^{(\frac{2}{3})}} d x

n = 0 \sum \infty \frac{ln ( n )}{n !}

y^{^{''}} - 4 y^{^{'}} + 3 y = 0, y (0) = 3, y^{^{'}} (0) = 2

x^{2} + 3 x