What is the derivative of sqrt(x^2+3x) ?

The derivative of sqrt(x^2+3x) is (2x+3)/(2sqrt(x^2+3x))

What is the first derivative of sqrt(x^2+3x) ?

The first derivative of sqrt(x^2+3x) is (2x+3)/(2sqrt(x^2+3x))

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derivative of

x^{2} + 3 x

\frac{2 x + 3}{2 x ^{2} + 3 x}

Solution steps

\frac{d}{d x} (x^{2} + 3 x)

Apply the chain rule:

\frac{1}{2 x ^{2} + 3 x} \frac{d}{d x} (x^{2} + 3 x)

= \frac{1}{2 x ^{2} + 3 x} \frac{d}{d x} (x^{2} + 3 x)

\frac{d}{d x} (x^{2} + 3 x) = 2 x + 3

= \frac{1}{2 x ^{2} + 3 x} (2 x + 3)

Simplify

\frac{1}{2 x ^{2} + 3 x} (2 x + 3) : \frac{2 x + 3}{2 x ^{2} + 3 x}

= \frac{2 x + 3}{2 x ^{2} + 3 x}

\frac{d}{d x} (5 x lo g_{4} (2 x - 1))

\frac{\partial}{\partial y} ((x - y)^{2})

a

y^{^{''}} - 8 y^{^{'}} + 14 y = 0, y (0) = 0, y^{^{'}} (0) = 1

\frac{\partial ^{2}}{\partial x ^{2}} (\frac{x y}{x - y})

What is the derivative of sqrt(x^2+3x) ?
The derivative of sqrt(x^2+3x) is (2x+3)/(2sqrt(x^2+3x))
What is the first derivative of sqrt(x^2+3x) ?
The first derivative of sqrt(x^2+3x) is (2x+3)/(2sqrt(x^2+3x))