What is the solution for y^'+2sin(2x)y=2sin(2x) ?

The solution for y^'+2sin(2x)y=2sin(2x) is y=e^{cos(2x)+c_{1}}+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+2sin(2x)y=2sin(2x)

y^{^{'}} + 2 sin (2 x) y = 2 sin (2 x)

y = e^{c o s (2 x) + c_{1}} + 1

Solution steps

y^{'} (x) + 2 sin (2 x) y = 2 sin (2 x)

Solve separable ODE:

y = e^{c o s (2 x) + c_{1}} + 1

y = e^{c o s (2 x) + c_{1}} + 1

\int \frac{e ^{\frac{1}{x}} + 2}{x ^{2}} d x

x^{2} - 2 x + 2, \frac{1}{2} (x - 4)^{2}, x = 0

\int_{0}^{\frac{π}{2}} 5 sin^{2} (3 x) d x

\int tan^{3} (x) sec^{3} (x) d x

a^{2 x}

What is the solution for y^'+2sin(2x)y=2sin(2x) ?
The solution for y^'+2sin(2x)y=2sin(2x) is y=e^{cos(2x)+c_{1}}+1