What is the solution for P^'=200e^{0.02t} ?

The solution for P^'=200e^{0.02t} is P(t)=10000e^{0.02t}+c_{1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

P^'=200e^{0.02t}

P^{^{'}} = 200 e^{0.02 t}

P (t) = 10000 e^{0.02 t} + c_{1}

Solution steps

P^{'} (t) = 200 e^{0.02 t}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

P (t) = \int 200 e^{0.02 t} d t

\int 200 e^{0.02 t} d t = 10000 e^{0.02 t} + c_{1}

P (t) = 10000 e^{0.02 t} + c_{1}

f (x) = x + 5

\int \frac{x ^{2}}{( x - 2 ) ^{3}} d x

\frac{\partial}{\partial x} (x^{2} - y^{2})

6 sin (x), 6 cos (2 x), [- \frac{π}{2}, \frac{π}{6}]

f (x) = \frac{1}{x + 2}

What is the solution for P^'=200e^{0.02t} ?
The solution for P^'=200e^{0.02t} is P(t)=10000e^{0.02t}+c_{1}