What is (\partial)/(\partial x)(sqrt(x^2-y^2)) ?

The answer to (\partial)/(\partial x)(sqrt(x^2-y^2)) is x/(sqrt(x^2-y^2))

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(\partial)/(\partial x)(sqrt(x^2-y^2))

\frac{\partial}{\partial x} (x^{2} - y^{2})

\frac{x}{x ^{2} - y ^{2}}

Solution steps

\frac{\partial}{\partial x} (x^{2} - y^{2})

Treat

y

as a constant

Apply the chain rule:

\frac{1}{2 x ^{2} - y ^{2}} \frac{\partial}{\partial x} (x^{2} - y^{2})

= \frac{1}{2 x ^{2} - y ^{2}} \frac{\partial}{\partial x} (x^{2} - y^{2})

\frac{\partial}{\partial x} (x^{2} - y^{2}) = 2 x

= \frac{1}{2 x ^{2} - y ^{2}} \cdot 2 x

Simplify

\frac{1}{2 x ^{2} - y ^{2}} \cdot 2 x : \frac{x}{x ^{2} - y ^{2}}

= \frac{x}{x ^{2} - y ^{2}}

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y^{^{''}} - 4 y^{^{'}} + 4 y = t e^{2 t}

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What is (\partial)/(\partial x)(sqrt(x^2-y^2)) ?
The answer to (\partial)/(\partial x)(sqrt(x^2-y^2)) is x/(sqrt(x^2-y^2))