What is the tangent of f(x)=sqrt(2x+3),\at x=3 ?

The tangent of f(x)=sqrt(2x+3),\at x=3 is y= 1/3 x+2

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tangent of f(x)=sqrt(2x+3),\at x=3

tangent of

f (x) = 2 x + 3, at x = 3

y = \frac{1}{3} x + 2

Solution steps

Find the tangent point:

(3, 3)

Find the slope of

f (x) = 2 x + 3 : \frac{df ( x )}{d x} = \frac{1}{2 x + 3}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{3}

Find the line with slope m=

\frac{1}{3}

and passing through

(3, 3) : y = \frac{1}{3} x + 2

y = \frac{1}{3} x + 2

\int_{0}^{π} 3 x^{2} + cos (x) d x

\frac{x}{x ^{- 1} + 12}

\frac{d}{d x} (\frac{- x ^{2} + 1}{( x ^{2} + 1 ) ^{2}})

\frac{\partial}{\partial x} (e^{- x} \cdot y)

arcsec (2 x)

What is the tangent of f(x)=sqrt(2x+3),\at x=3 ?
The tangent of f(x)=sqrt(2x+3),\at x=3 is y= 1/3 x+2