What is (\partial)/(\partial x)(3x^2y^2-2) ?

The answer to (\partial)/(\partial x)(3x^2y^2-2) is 6xy^2

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(\partial)/(\partial x)(3x^2y^2-2)

\frac{\partial}{\partial x} (3 x^{2} y^{2} - 2)

6 x y^{2}

Solution steps

\frac{\partial}{\partial x} (3 x^{2} y^{2} - 2)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2} y^{2}) - \frac{\partial}{\partial x} (2)

\frac{\partial}{\partial x} (3 x^{2} y^{2}) = 6 y^{2} x

\frac{\partial}{\partial x} (2) = 0

= 6 y^{2} x - 0

Simplify

= 6 x y^{2}

\frac{d}{d x} (e^{- 2 x} (1 - x))

\frac{d}{d x} (10 (3 x^{2} + 7 x - 3)^{10})

\int \frac{2 x}{( 4 - x ) ^{3}} d x

\frac{d}{d x} (5 ln (x^{5}))

(e^{x})^{^{'}}

What is (\partial)/(\partial x)(3x^2y^2-2) ?
The answer to (\partial)/(\partial x)(3x^2y^2-2) is 6xy^2