What is the (e^{sqrt(x)})^' ?

The (e^{sqrt(x)})^' is (e^{sqrt(x)})/(2sqrt(x))

What is the first (e^{sqrt(x)})^' ?

The first (e^{sqrt(x)})^' is (e^{sqrt(x)})/(2sqrt(x))

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(e^{x})^{^{'}}

\frac{e ^{x}}{2 x}

Solution steps

(e^{x})^{'}

Apply the chain rule:

e^{x} (x)^{'}

= e^{x} (x)^{'}

(x)^{'} = \frac{1}{2 x}

= e^{x} \frac{1}{2 x}

Simplify

e^{x} \frac{1}{2 x} : \frac{e ^{x}}{2 x}

= \frac{e ^{x}}{2 x}

\int 4 x^{- \frac{6}{7}} d x

x y^{^{'}} + (2 x - 3) y = 4 x^{4}

\frac{( s + 1 )}{( s + 2 ) ( s - 3 )}

4 y - y^{^{''}} = 10 e^{- 3 x}

\int ln (x) + 1 d x

What is the (e^{sqrt(x)})^' ?
The (e^{sqrt(x)})^' is (e^{sqrt(x)})/(2sqrt(x))
What is the first (e^{sqrt(x)})^' ?
The first (e^{sqrt(x)})^' is (e^{sqrt(x)})/(2sqrt(x))