What is the derivative of (1+e^{x^2})^3 ?

The derivative of (1+e^{x^2})^3 is 6e^{x^2}x(1+e^{x^2})^2

What is the first derivative of (1+e^{x^2})^3 ?

The first derivative of (1+e^{x^2})^3 is 6e^{x^2}x(1+e^{x^2})^2

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derivative of

(1 + e^{x^{2}})^{3}

6 e^{x^{2}} x (1 + e^{x^{2}})^{2}

Solution steps

\frac{d}{d x} ((1 + e^{x^{2}})^{3})

Apply the chain rule:

3 (1 + e^{x^{2}})^{2} \frac{d}{d x} (1 + e^{x^{2}})

= 3 (1 + e^{x^{2}})^{2} \frac{d}{d x} (1 + e^{x^{2}})

\frac{d}{d x} (1 + e^{x^{2}}) = 2 e^{x^{2}} x

= 3 (1 + e^{x^{2}})^{2} \cdot 2 e^{x^{2}} x

Simplify

= 6 e^{x^{2}} x (1 + e^{x^{2}})^{2}

\frac{\partial}{\partial z} (x + \frac{y}{z})

n = 0 \sum \infty \frac{1}{n + 4}

\int x (x^{2} + 1)^{10} d x

y = 6 - x^{2}, y = x

\int \frac{3}{17 x ^{2}} d x

What is the derivative of (1+e^{x^2})^3 ?
The derivative of (1+e^{x^2})^3 is 6e^{x^2}x(1+e^{x^2})^2
What is the first derivative of (1+e^{x^2})^3 ?
The first derivative of (1+e^{x^2})^3 is 6e^{x^2}x(1+e^{x^2})^2