What is the sum from n=0 to infinity of 1/(n+4) ?

The sum from n=0 to infinity of 1/(n+4) is diverges

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sum from n=0 to infinity of 1/(n+4)

n = 0 \sum \infty \frac{1}{n + 4}

diverges

Solution steps

n = 0 \sum \infty \frac{1}{n + 4}

Apply Series Integral Test:

diverges

= diverges

\int x (x^{2} + 1)^{10} d x

y = 6 - x^{2}, y = x

\int \frac{3}{17 x ^{2}} d x

n = 0 \sum \infty \frac{n}{n}

\frac{d}{d x} (3 x^{2} + \frac{16 x}{3} - 2)

What is the sum from n=0 to infinity of 1/(n+4) ?
The sum from n=0 to infinity of 1/(n+4) is diverges