What is the limit as x approaches 0+of (sin^2(x))/x ?

The limit as x approaches 0+of (sin^2(x))/x is 0

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limit as x approaches 0+of (sin^2(x))/x

x \to 0 + lim (\frac{sin ^{2} ( x )}{x})

0

Solution steps

x \to 0 + lim (\frac{sin ^{2} ( x )}{x})

Apply L'Hopital's Rule

: x \to 0 + lim (\frac{sin ( 2 x )}{1})

= x \to 0 + lim (\frac{sin ( 2 x )}{1})

Plug in the value

x = 0

= \frac{sin ( 2 \cdot 0 )}{1}

Simplify

\frac{sin ( 2 \cdot 0 )}{1} : 0

= 0

x^{2} + x y - y^{2} = - 1, (1, 2)

(x - 7) (2 x + 4)

x \to 1 lim (\frac{x}{x ^{2} + 4})

y = (4 x^{3} + 5) (x^{4} - 3 x)

n = 1 \sum \infty n + \frac{1}{n ^{2}}

What is the limit as x approaches 0+of (sin^2(x))/x ?
The limit as x approaches 0+of (sin^2(x))/x is 0