What is the sum from n=1 to infinity of n+1/(n^2) ?

The sum from n=1 to infinity of n+1/(n^2) is diverges

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sum from n=1 to infinity of n+1/(n^2)

n = 1 \sum \infty n + \frac{1}{n ^{2}}

diverges

Solution steps

n = 1 \sum \infty n + \frac{1}{n ^{2}}

Apply Series Divergence Test:

diverges

= diverges

\frac{d y}{d x} = 2 x

\int_{1}^{5} π (x - 1) d x

n = 1 \sum \infty n 7

\int \frac{( y + 1 ) ^{2}}{y} d y

2 - x^{2}

What is the sum from n=1 to infinity of n+1/(n^2) ?
The sum from n=1 to infinity of n+1/(n^2) is diverges