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Popular >

t=y+y^'

Solution

t = y + y^{^{'}}

Solution

y = t - 1 + \frac{c _{1}}{e ^{t}}

Solution steps

t = y + y^{'} (t)

Solve linear ODE:

y = t - 1 + \frac{c _{1}}{e ^{t}}

y = t - 1 + \frac{c _{1}}{e ^{t}}

Graph

Popular Examples

integral of 5-x^2

\int 5 - x^{2} d x

integral from-3 to 3 of (2x^4-3x^3)

\int_{- 3}^{3} (2 x^{4} - 3 x^{3}) d x

integral of xex

\int x e x d x

derivative of sin(sin(sin(x)))derivative of

sin (sin (sin (x)))

limit as x approaches-5+of-(9x)/(x+5)

x \to - 5 + lim (- \frac{9 x}{x + 5})

Frequently Asked Questions (FAQ)

What is the solution for t=y+y^' ?
The solution for t=y+y^' is y=t-1+(c_{1})/(e^t)