What is the tangent of f(x)=e^x,\at x=0.3 ?

The tangent of f(x)=e^x,\at x=0.3 is y=1.34985…x+e^{0.3}-0.40495…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=e^x,\at x=0.3

tangent of

f (x) = e^{x}, at x = 0.3

y = 1.34985 \dots x + e^{0.3} - 0.40495 \dots

Solution steps

Find the tangent point:

(0.3, e^{0.3})

Find the slope of

f (x) = e^{x} : \frac{df ( x )}{d x} = e^{x}

Compute the slope of

f (x) = e^{x}

x = 0.3 : m = 1.34985 \dots

Find the line with slope m=

1.34985 \dots

and passing through

(0.3, e^{0.3}) : y = 1.34985 \dots x + e^{0.3} - 0.40495 \dots

y = 1.34985 \dots x + e^{0.3} - 0.40495 \dots

32 x

t^{2} cos (k t)

\int_{1}^{2} (3 x^{2} + 2 x + 1) d x

\frac{\partial}{\partial y} ((x y)^{\frac{1}{3}})

\int x 5 - 2 x d x

What is the tangent of f(x)=e^x,\at x=0.3 ?
The tangent of f(x)=e^x,\at x=0.3 is y=1.34985…x+e^{0.3}-0.40495…