What is the derivative of 0.6cos(2x) ?

The derivative of 0.6cos(2x) is -1.2sin(2x)

What is the first derivative of 0.6cos(2x) ?

The first derivative of 0.6cos(2x) is -1.2sin(2x)

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\frac{d}{d x} (0.6 cos (2 x))

- 1.2 sin (2 x)

Solution steps

\frac{d}{d x} (0.6 cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 0.6 \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 0.6 (- sin (2 x) \cdot 2)

Simplify

= - 1.2 sin (2 x)

\frac{\partial}{\partial x} (- 1 - 4 y)

x \to 0 lim (\frac{sin ^{2} ( 6 x )}{7})

\frac{1}{s ( s ^{2} - 1 )}

f (x) = \frac{1}{x + 2}, at x = 7

f (x) = \frac{x ^{2}}{x + 5}

What is the derivative of 0.6cos(2x) ?
The derivative of 0.6cos(2x) is -1.2sin(2x)
What is the first derivative of 0.6cos(2x) ?
The first derivative of 0.6cos(2x) is -1.2sin(2x)