What is the limit as x approaches 0+of 2+x^9ln(x) ?

The limit as x approaches 0+of 2+x^9ln(x) is 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0+of 2+x^9ln(x)

x \to 0 + lim (2 + x^{9} ln (x))

2

Solution steps

x \to 0 + lim (2 + x^{9} ln (x))

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 + lim (2) + x \to 0 + lim (x^{9} ln (x))

x \to 0 + lim (2) = 2

x \to 0 + lim (x^{9} ln (x)) = 0

= 2 + 0

Simplify

= 2

\frac{\partial}{\partial y} (x y e^{yz})

\int 9 e^{u} d u

f (x) = x^{2} + x, (7, 56)

\frac{\partial}{\partial x} (\frac{7 x - 4 y}{7 x + 4 y})

\int t \cdot e^{- s t} d t

What is the limit as x approaches 0+of 2+x^9ln(x) ?
The limit as x approaches 0+of 2+x^9ln(x) is 2