What is the derivative of (ln(4x)^2) ?

The derivative of (ln(4x)^2) is (2ln(4x))/x

What is the first derivative of (ln(4x)^2) ?

The first derivative of (ln(4x)^2) is (2ln(4x))/x

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\frac{d}{d x} ((ln (4 x))^{2})

\frac{2 ln ( 4 x )}{x}

Solution steps

\frac{d}{d x} ((ln (4 x))^{2})

Apply the chain rule:

2 ln (4 x) \frac{d}{d x} (ln (4 x))

= 2 ln (4 x) \frac{d}{d x} (ln (4 x))

\frac{d}{d x} (ln (4 x)) = \frac{1}{x}

= 2 ln (4 x) \frac{1}{x}

Simplify

2 ln (4 x) \frac{1}{x} : \frac{2 ln ( 4 x )}{x}

= \frac{2 ln ( 4 x )}{x}

y^{^{'}} = 5 y + y^{3}

\int_{- π}^{π} x^{2} cos (n x) d x

\int_{0}^{4} π (x)^{2} d x

y^{^{'}} + 3 y = 15 - e^{t}

x \to 5 - lim (e^{\frac{3}{( 5 - x )}})

What is the derivative of (ln(4x)^2) ?
The derivative of (ln(4x)^2) is (2ln(4x))/x
What is the first derivative of (ln(4x)^2) ?
The first derivative of (ln(4x)^2) is (2ln(4x))/x