What is the tangent of y=(x^2-35)^7,\at x=6 ?

The tangent of y=(x^2-35)^7,\at x=6 is y=84x-503

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tangent of y=(x^2-35)^7,\at x=6

tangent of

y = (x^{2} - 35)^{7}, at x = 6

y = 84 x - 503

Solution steps

Find the tangent point:

(6, 1)

Find the slope of

y = (x^{2} - 35)^{7} : \frac{d y}{d x} = 14 x (x^{2} - 35)^{6}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 84

Find the line with slope m=

84

and passing through

(6, 1) : y = 84 x - 503

y = 84 x - 503

f (x) = \frac{2 x ^{2}}{( 1 - 2 x ) 4}, at x = 2

x \to - \infty lim (3 x)

\int x sin (- x) d x

\frac{s + 1}{s ^{2} + s - 1}

x \to 0 lim (\frac{1}{2} + e^{\frac{1}{x}})

What is the tangent of y=(x^2-35)^7,\at x=6 ?
The tangent of y=(x^2-35)^7,\at x=6 is y=84x-503