What is area y=(100)/(25+x^2),y=1 ?

The answer to area y=(100)/(25+x^2),y=1 is (40pi)/3-10sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=(100)/(25+x^2),y=1

area

y = \frac{100}{25 + x ^{2}}, y = 1

\frac{40 π}{3} - 103

Decimal

24.56739 \dots

Solution steps

Apply the area formula:

\int_{- 53}^{53} \frac{100}{25 + x ^{2}} - 1 d x

Solve

\int_{- 53}^{53} \frac{100}{25 + x ^{2}} - 1 d x : \frac{40 π}{3} - 103

The area is:

= \frac{40 π}{3} - 103

(4 y + 2 x - 5) d x + (6 y + 4 x - 1) d y = 0

\frac{d}{d y} (\frac{x}{x ^{2} + y ^{2}})

y^{^{''}} - y^{^{'}} - 6 y = e^{- 2 x}

f (x) = \frac{2 x - 3}{2 x + 5}, at x = - 1

x \to 0 lim (3 x^{2} - 4 x + 5)

What is area y=(100)/(25+x^2),y=1 ?
The answer to area y=(100)/(25+x^2),y=1 is (40pi)/3-10sqrt(3)