What is the tangent of f(x)=1+cos(x),\at x= pi/2 ?

The tangent of f(x)=1+cos(x),\at x= pi/2 is y=-x+1+pi/2

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tangent of f(x)=1+cos(x),\at x= pi/2

tangent of

f (x) = 1 + cos (x), at x = \frac{π}{2}

y = - x + 1 + \frac{π}{2}

Solution steps

Find the tangent point:

(\frac{π}{2}, 1)

Find the slope of

f (x) = 1 + cos (x) : \frac{df ( x )}{d x} = - sin (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 1

Find the line with slope m=

- 1

and passing through

(\frac{π}{2}, 1) : y = - x + 1 + \frac{π}{2}

y = - x + 1 + \frac{π}{2}

\frac{d x}{d t} + t^{5} x^{7} + \frac{x}{t} = 0

f (x) = x cos (x)

\int \frac{1}{( x + 1 ) x} d x

\frac{\partial}{\partial t} (\frac{1}{t})

\int cos (I n (x)) d x

What is the tangent of f(x)=1+cos(x),\at x= pi/2 ?
The tangent of f(x)=1+cos(x),\at x= pi/2 is y=-x+1+pi/2