What is the solution for (dy)/(dx)=-1/(2y) ?

The solution for (dy)/(dx)=-1/(2y) is y=sqrt(-x-c_{1)},y=-sqrt(-x-c_{1)}

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(dy)/(dx)=-1/(2y)

\frac{d y}{d x} = - \frac{1}{2 y}

y = - x - c_{1}, y = - - x - c_{1}

Solution steps

\frac{d y}{d x} = - \frac{1}{2 y}

Solve separable ODE:

y = - x - c_{1}, y = - - x - c_{1}

y = - x - c_{1}, y = - - x - c_{1}

\int_{- 1}^{1} - 2 y^{2} + 2 d y

y^{^{''}} + 18 y^{^{'}} + 80 y = 0

\int_{0}^{1} \frac{25}{x ^{5}} d x

\int_{- 3}^{0} \frac{9}{9 x + 4} d x

\int \frac{20}{1 + x ^{2}} d x

What is the solution for (dy)/(dx)=-1/(2y) ?
The solution for (dy)/(dx)=-1/(2y) is y=sqrt(-x-c_{1)},y=-sqrt(-x-c_{1)}