What is area 6sin(x)-6cos(2x),[0, pi/2 ] ?

The answer to area 6sin(x)-6cos(2x),[0, pi/2 ] is 9sqrt(3)-6

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area 6sin(x)-6cos(2x),[0, pi/2 ]

area

6 sin (x) - 6 cos (2 x), [0, \frac{π}{2}]

93 - 6

Decimal Notation

9.58845 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{2}} ∣ 6 sin (x) - 6 cos (2 x) ∣ d x

Solve

\int_{0}^{\frac{π}{2}} ∣ 6 sin (x) - 6 cos (2 x) ∣ d x : 93 - 6

The area is:

= 93 - 6

\frac{\partial}{\partial x} (- x sin (x y))

\frac{d}{d x} (x \cdot e^{x} \cdot sin (x))

\int_{8}^{10} \frac{y}{y ^{2} - 4 y - 5} d y

f (x) = (- 2 x^{3} + x^{2} - 2 x - 1) x^{3}

y^{^{''}} + 64 y = sin (8 t)

What is area 6sin(x)-6cos(2x),[0, pi/2 ] ?
The answer to area 6sin(x)-6cos(2x),[0, pi/2 ] is 9sqrt(3)-6