What is the solution for y^{''}+64y=sin(8t) ?

The solution for y^{''}+64y=sin(8t) is y=c_{1}cos(8t)+c_{2}sin(8t)-(tcos(8t))/(16)

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y^{''}+64y=sin(8t)

y^{^{''}} + 64 y = sin (8 t)

y = c_{1} cos (8 t) + c_{2} sin (8 t) - \frac{t cos ( 8 t )}{16}

Solution steps

y^{''} (t) + 64 y = sin (8 t)

Solve linear ODE:

y = c_{1} cos (8 t) + c_{2} sin (8 t) - \frac{t cos ( 8 t )}{16}

y = c_{1} cos (8 t) + c_{2} sin (8 t) - \frac{t cos ( 8 t )}{16}

x \to 0 lim (x^{2} + 4)

\frac{d}{d x} (\frac{2}{9 x ^{3}})

d y = x^{2} sin (8 x) d x

\frac{\partial}{\partial y} (x^{2} y^{3} sin (x - 2 y))

x \to 7 lim (x + 6)

What is the solution for y^{''}+64y=sin(8t) ?
The solution for y^{''}+64y=sin(8t) is y=c_{1}cos(8t)+c_{2}sin(8t)-(tcos(8t))/(16)