What is the limit as x approaches 0 of sqrt(x^2+4) ?

The limit as x approaches 0 of sqrt(x^2+4) is 2

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limit as x approaches 0 of sqrt(x^2+4)

x \to 0 lim (x^{2} + 4)

2

Solution steps

x \to 0 lim (x^{2} + 4)

Plug in the value

x = 0

= 0^{2} + 4

Simplify

0^{2} + 4 : 2

= 2

\frac{d}{d x} (\frac{2}{9 x ^{3}})

d y = x^{2} sin (8 x) d x

\frac{\partial}{\partial y} (x^{2} y^{3} sin (x - 2 y))

x \to 7 lim (x + 6)

y^{^{'}} = \frac{x}{14 y}

What is the limit as x approaches 0 of sqrt(x^2+4) ?
The limit as x approaches 0 of sqrt(x^2+4) is 2