What is the integral from 1 to 2 of x^4+1/(4x^4) ?

The integral from 1 to 2 of x^4+1/(4x^4) is 3011/480

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 2 of x^4+1/(4x^4)

\int_{1}^{2} x^{4} + \frac{1}{4 x ^{4}} d x

\frac{3011}{480}

Decimal Notation

6.27291 \dots

Solution steps

\int_{1}^{2} x^{4} + \frac{1}{4 x ^{4}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{4} d x + \int_{1}^{2} \frac{1}{4 x ^{4}} d x

\int_{1}^{2} x^{4} d x = \frac{31}{5}

\int_{1}^{2} \frac{1}{4 x ^{4}} d x = \frac{7}{96}

= \frac{31}{5} + \frac{7}{96}

Simplify

\frac{31}{5} + \frac{7}{96} : \frac{3011}{480}

= \frac{3011}{480}

\int_{0}^{5} x 25 - x^{2} d x

15 cos (3 t)

\frac{5 d x}{d t} = x^{2}

n = 0 \sum \infty q^{2 n}

x \to 0 lim (\frac{1}{x + 1})

What is the integral from 1 to 2 of x^4+1/(4x^4) ?
The integral from 1 to 2 of x^4+1/(4x^4) is 3011/480