What is (\partial)/(\partial x)(3x^4y^8+7x^5y^6) ?

The answer to (\partial)/(\partial x)(3x^4y^8+7x^5y^6) is 12y^8x^3+35y^6x^4

Popular >

(\partial)/(\partial x)(3x^4y^8+7x^5y^6)

\frac{\partial}{\partial x} (3 x^{4} y^{8} + 7 x^{5} y^{6})

12 y^{8} x^{3} + 35 y^{6} x^{4}

Solution steps

\frac{\partial}{\partial x} (3 x^{4} y^{8} + 7 x^{5} y^{6})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{4} y^{8}) + \frac{\partial}{\partial x} (7 x^{5} y^{6})

\frac{\partial}{\partial x} (3 x^{4} y^{8}) = 12 y^{8} x^{3}

\frac{\partial}{\partial x} (7 x^{5} y^{6}) = 35 y^{6} x^{4}

= 12 y^{8} x^{3} + 35 y^{6} x^{4}

\int 7 (1 + tan^{2} (a)) d a

h (x) = \frac{8}{x} - \frac{2}{x ^{3}} + \frac{1}{x ^{4}}

y^{^{''}} - 14 y^{^{'}} + 85 y = 0

\frac{\partial}{\partial x} (\frac{4}{x})

- \frac{12}{s ^{5}}

What is (\partial)/(\partial x)(3x^4y^8+7x^5y^6) ?
The answer to (\partial)/(\partial x)(3x^4y^8+7x^5y^6) is 12y^8x^3+35y^6x^4