What is the derivative of e^{x^3+8x} ?

The derivative of e^{x^3+8x} is e^{x^3+8x}(3x^2+8)

What is the first derivative of e^{x^3+8x} ?

The first derivative of e^{x^3+8x} is e^{x^3+8x}(3x^2+8)

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\frac{d}{d x} (e^{x^{3} + 8 x})

e^{x^{3} + 8 x} (3 x^{2} + 8)

Solution steps

\frac{d}{d x} (e^{x^{3} + 8 x})

Apply the chain rule:

e^{x^{3} + 8 x} \frac{d}{d x} (x^{3} + 8 x)

= e^{x^{3} + 8 x} \frac{d}{d x} (x^{3} + 8 x)

\frac{d}{d x} (x^{3} + 8 x) = 3 x^{2} + 8

= e^{x^{3} + 8 x} (3 x^{2} + 8)

2 1 + sin (2 t)

\int (x + 1) 8 x + 9 d x

\frac{2 x}{( 1 + x ^{2} ) ^{2}}

\frac{d}{d x} (x^{3} + 5 x + 7)

e^{- t} + 2 e^{- 2 t} + t e^{- 3 t}

What is the derivative of e^{x^3+8x} ?
The derivative of e^{x^3+8x} is e^{x^3+8x}(3x^2+8)
What is the first derivative of e^{x^3+8x} ?
The first derivative of e^{x^3+8x} is e^{x^3+8x}(3x^2+8)