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Popular >

d/(dt)(asin(3t)+bcos(3t))

Solution

\frac{d}{d t} (a sin (3 t) + b cos (3 t))

Solution

a cos (3 t) \cdot 3 - 3 b sin (3 t)

Solution steps

\frac{d}{d t} (a sin (3 t) + b cos (3 t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (a sin (3 t)) + \frac{d}{d t} (b cos (3 t))

\frac{d}{d t} (a sin (3 t)) = a cos (3 t) \cdot 3

\frac{d}{d t} (b cos (3 t)) = - 3 b sin (3 t)

= a cos (3 t) \cdot 3 - 3 b sin (3 t)

Graph

Popular Examples

sum from n=1 to infinity of 1/(5^{1/n)}

n = 1 \sum \infty \frac{1}{5 ^{\frac{1}{n}}}

limit as x approaches-3 of (x+3)/(x^2-9)

x \to - 3 lim (\frac{x + 3}{x ^{2} - 9})

derivative of f(x)=2xe^x derivative of

f (x) = 2 x e^{x}

derivative of (xe^x/(x+1))

\frac{d}{d x} (\frac{x e ^{x}}{x + 1})

integral of (x^2-3x+5)e^x

\int (x^{2} - 3 x + 5) e^{x} d x

Frequently Asked Questions (FAQ)

What is the d/(dt)(asin(3t)+bcos(3t)) ?
The d/(dt)(asin(3t)+bcos(3t)) is acos(3t)*3-3bsin(3t)
What is the first d/(dt)(asin(3t)+bcos(3t)) ?
The first d/(dt)(asin(3t)+bcos(3t)) is acos(3t)*3-3bsin(3t)