What is the tangent of ((1+y))/((1+x)) ?

The tangent of ((1+y))/((1+x)) is y=-1/(a_{0)^2}x+2/(a_{0)}

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tangent of ((1+y))/((1+x))

tangent of

\frac{( 1 + y )}{( 1 + x )}

y = - \frac{1}{a _{0}^{2}} x + \frac{2}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{1}{a _{0}})

Find the slope of

y = \frac{1 + y}{1 + x} : \frac{d y}{d x} = - \frac{1}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{a _{0}^{2}}

Find the line with slope m=

- \frac{1}{a _{0}^{2}}

and passing through

(a_{0}, \frac{1}{a _{0}}) : y = - \frac{1}{a _{0}^{2}} x + \frac{2}{a _{0}}

y = - \frac{1}{a _{0}^{2}} x + \frac{2}{a _{0}}

x^{2} - 1

\frac{d y}{d x} = 4 x e^{2 x}

\frac{\partial}{\partial x} (x + ln (5 x + y))

\int 5 x + 1 d x

2 x^{2} + x - 1, at x = 1

What is the tangent of ((1+y))/((1+x)) ?
The tangent of ((1+y))/((1+x)) is y=-1/(a_{0)^2}x+2/(a_{0)}