What is the derivative of ln(kx) ?

The derivative of ln(kx) is 1/x

What is the first derivative of ln(kx) ?

The first derivative of ln(kx) is 1/x

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derivative of

ln (k x)

\frac{1}{x}

Solution steps

\frac{d}{d x} (ln (k x))

Apply the chain rule:

\frac{1}{k x} \frac{d}{d x} (k x)

= \frac{1}{k x} \frac{d}{d x} (k x)

\frac{d}{d x} (k x) = k

= \frac{1}{k x} k

Simplify

\frac{1}{k x} k : \frac{1}{x}

= \frac{1}{x}

y^{^{'}} - 3 y = 2 x + 1

\int \frac{x}{1 + 6 x - 3 x ^{2}} d x

\frac{\partial}{\partial y} (x^{2} - x)

x y^{^{'}} + y = y^{- 2}

\frac{d}{d x} (\frac{π}{2} x)