What is area x=y^4,sqrt(2-x),y=0 ?

The answer to area x=y^4,sqrt(2-x),y=0 is No Solution

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area x=y^4,sqrt(2-x),y=0

area

x = y^{4}, 2 - x, y = 0

No Solution

Solution steps

Isolate

y

for

To find the intersection points solve

f_{i} (x) = f_{j} (x)

No Solution for

x \in R

0 = 2 - x : x = 2

Curves not bounded

= No Solution

\frac{4 x - 6}{2 x ^{2} + x - 2}

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\frac{d}{d x} (e^{3 y - x^{2}})

\int (2 x - 4)^{5} d x

\frac{\partial}{\partial x} (4 x^{2} + 3 y^{2} - 4 x y + x)

What is area x=y^4,sqrt(2-x),y=0 ?
The answer to area x=y^4,sqrt(2-x),y=0 is No Solution