What is the limit as x approaches 1+of 6/(x^3-1) ?

The limit as x approaches 1+of 6/(x^3-1) is infinity

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limit as x approaches 1+of 6/(x^3-1)

x \to 1 + lim (\frac{6}{x ^{3} - 1})

\infty

Solution steps

x \to 1 + lim (\frac{6}{x ^{3} - 1})

For

x

approaching

1

from the right

, x > 1 \Rightarrow x^{3} - 1 > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

\int x^{2} - x^{3} d x

\int_{0}^{1} x^{3} e^{x^{2}} d x

\int arctan (x y) d x

y = \frac{5}{x}, y = \frac{10}{x ^{2}}, x = 6

\int \frac{y ^{2}}{y ^{3} + 1} d y

What is the limit as x approaches 1+of 6/(x^3-1) ?
The limit as x approaches 1+of 6/(x^3-1) is infinity