What is area y= 5/x ,y=(10)/(x^2),x=6 ?

The answer to area y= 5/x ,y=(10)/(x^2),x=6 is 5ln(3)-10/3

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area y= 5/x ,y=(10)/(x^2),x=6

area

y = \frac{5}{x}, y = \frac{10}{x ^{2}}, x = 6

5 ln (3) - \frac{10}{3}

Decimal Notation

2.15972 \dots

Solution steps

Apply the area formula:

\int_{2}^{6} \frac{5}{x} - \frac{10}{x ^{2}} d x

Solve

\int_{2}^{6} \frac{5}{x} - \frac{10}{x ^{2}} d x : 5 ln (3) - \frac{10}{3}

The area is:

= 5 ln (3) - \frac{10}{3}

\int \frac{y ^{2}}{y ^{3} + 1} d y

\int \frac{( e ^{x} )}{2} d x

x \to \frac{1}{2} lim (\frac{x ^{2}}{2})

3 x^{2} - x + 1

f (x) = x^{2} + 6 (- 5.31)

What is area y= 5/x ,y=(10)/(x^2),x=6 ?
The answer to area y= 5/x ,y=(10)/(x^2),x=6 is 5ln(3)-10/3