What is the integral of ((e^x))/2 ?

The integral of ((e^x))/2 is 1/2 e^x+C

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integral of ((e^x))/2

\int \frac{( e ^{x} )}{2} d x

\frac{1}{2} e^{x} + C

Solution steps

\int \frac{e ^{x}}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= \frac{1}{2} e^{x}

Add a constant to the solution

= \frac{1}{2} e^{x} + C

x \to \frac{1}{2} lim (\frac{x ^{2}}{2})

3 x^{2} - x + 1

f (x) = x^{2} + 6 (- 5.31)

\int \frac{1}{1 x} d x

f (x) = x^{3} - 6 x, at x = 2