What is the derivative of sqrt(3x^2-x+1) ?

The derivative of sqrt(3x^2-x+1) is (6x-1)/(2sqrt(3x^2-x+1))

What is the first derivative of sqrt(3x^2-x+1) ?

The first derivative of sqrt(3x^2-x+1) is (6x-1)/(2sqrt(3x^2-x+1))

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derivative of

3 x^{2} - x + 1

\frac{6 x - 1}{2 3 x ^{2} - x + 1}

Solution steps

\frac{d}{d x} (3 x^{2} - x + 1)

Apply the chain rule:

\frac{1}{2 3 x ^{2} - x + 1} \frac{d}{d x} (3 x^{2} - x + 1)

= \frac{1}{2 3 x ^{2} - x + 1} \frac{d}{d x} (3 x^{2} - x + 1)

\frac{d}{d x} (3 x^{2} - x + 1) = 6 x - 1

= \frac{1}{2 3 x ^{2} - x + 1} (6 x - 1)

Simplify

\frac{1}{2 3 x ^{2} - x + 1} (6 x - 1) : \frac{6 x - 1}{2 3 x ^{2} - x + 1}

= \frac{6 x - 1}{2 3 x ^{2} - x + 1}

f (x) = x^{2} + 6 (- 5.31)

\int \frac{1}{1 x} d x

f (x) = x^{3} - 6 x, at x = 2

f (x) = cos^{3} (2 + x)

\int e^{- x} sin (3 x) d x

What is the derivative of sqrt(3x^2-x+1) ?
The derivative of sqrt(3x^2-x+1) is (6x-1)/(2sqrt(3x^2-x+1))
What is the first derivative of sqrt(3x^2-x+1) ?
The first derivative of sqrt(3x^2-x+1) is (6x-1)/(2sqrt(3x^2-x+1))