What is the d/(d{x)}({x}^2+{y}^2+{z}^2) ?

The d/(d{x)}({x}^2+{y}^2+{z}^2) is 2{x}

What is the first d/(d{x)}({x}^2+{y}^2+{z}^2) ?

The first d/(d{x)}({x}^2+{y}^2+{z}^2) is 2{x}

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\frac{d}{d x} (x^{2} + y^{2} + z^{2})

2 x

Solution steps

\frac{d}{d x} (x^{2} + y^{2} + z^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (y^{2}) + \frac{d}{d x} (z^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (y^{2}) = 0

\frac{d}{d x} (z^{2}) = 0

= 2 x + 0 + 0

Simplify

= 2 x

y = cos (x), y = 2 - cos (x), 0 \leq x \leq 2 π

\frac{d}{d y} (5 x + 4 y)

\int_{- 1}^{4} (2 x + 4)^{2} d x

\frac{d}{d x} (ln (\frac{2 x}{3}))

\frac{d}{d x} (\frac{1}{( 1 - x ) ^{4}})

What is the d/(d{x)}({x}^2+{y}^2+{z}^2) ?
The d/(d{x)}({x}^2+{y}^2+{z}^2) is 2{x}
What is the first d/(d{x)}({x}^2+{y}^2+{z}^2) ?
The first d/(d{x)}({x}^2+{y}^2+{z}^2) is 2{x}