What is the d/(dt)(e^{tan(t)}) ?

The d/(dt)(e^{tan(t)}) is e^{tan(t)}sec^2(t)

What is the first d/(dt)(e^{tan(t)}) ?

The first d/(dt)(e^{tan(t)}) is e^{tan(t)}sec^2(t)

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\frac{d}{d t} (e^{t a n (t)})

e^{t a n (t)} sec^{2} (t)

Solution steps

\frac{d}{d t} (e^{t a n (t)})

Apply the chain rule:

e^{t a n (t)} \frac{d}{d t} (tan (t))

= e^{t a n (t)} \frac{d}{d t} (tan (t))

\frac{d}{d t} (tan (t)) = sec^{2} (t)

= e^{t a n (t)} sec^{2} (t)

\frac{d ^{4}}{d x ^{4}} (e^{x^{2}})

12 x^{2} y + y^{^{'}} = - 2 x^{2}

\int \frac{17}{9 - 25 x ^{2}} d x

\int e^{3 y} y d y

\frac{d}{d x} (\frac{x - x ^{2}}{x - 1})

What is the d/(dt)(e^{tan(t)}) ?
The d/(dt)(e^{tan(t)}) is e^{tan(t)}sec^2(t)
What is the first d/(dt)(e^{tan(t)}) ?
The first d/(dt)(e^{tan(t)}) is e^{tan(t)}sec^2(t)