What is the integral of (x^2*\sqrt[3]{x}) ?

The integral of (x^2*\sqrt[3]{x}) is 1/3 x^3\sqrt[3]{x}-1/30 x^{10/3}+C

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integral of (x^2*\sqrt[3]{x})

Solution steps

Apply Integration By Parts

\int \frac{1}{9} x^{\frac{7}{3}} d x = \frac{1}{30} x^{\frac{10}{3}}

Add a constant to the solution

\int \frac{7 sin ( 2 x )}{1 + cos ^{4} ( x )} d x

\frac{d}{d x} ((x^{11} - 2)^{3})

x^{2} (x^{3} + 5)^{3}

\int \frac{w + 1}{w ^{2} + 2 w} d w

\frac{\partial}{\partial y} (x^{3} y^{5} - 2 x^{2} y + x)

What is the integral of (x^2*\sqrt[3]{x}) ?
The integral of (x^2*\sqrt[3]{x}) is 1/3 x^3\sqrt[3]{x}-1/30 x^{10/3}+C