What is the d/(dt)(-4t^2+176t+100) ?

The d/(dt)(-4t^2+176t+100) is -8t+176

What is the first d/(dt)(-4t^2+176t+100) ?

The first d/(dt)(-4t^2+176t+100) is -8t+176

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\frac{d}{d t} (- 4 t^{2} + 176 t + 100)

- 8 t + 176

Solution steps

\frac{d}{d t} (- 4 t^{2} + 176 t + 100)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (4 t^{2}) + \frac{d}{d t} (176 t) + \frac{d}{d t} (100)

\frac{d}{d t} (4 t^{2}) = 8 t

\frac{d}{d t} (176 t) = 176

\frac{d}{d t} (100) = 0

= - 8 t + 176 + 0

Simplify

= - 8 t + 176

\frac{d}{d x} (sec (x^{2} + 2))

\int_{\frac{π}{9}}^{\infty} \frac{2}{x} d x

n = 2 \sum \infty \frac{5}{7 ^{n}}

\frac{\partial}{\partial y} (4 x^{2} y^{3})

\frac{\partial}{\partial x} (ln (x))

What is the d/(dt)(-4t^2+176t+100) ?
The d/(dt)(-4t^2+176t+100) is -8t+176
What is the first d/(dt)(-4t^2+176t+100) ?
The first d/(dt)(-4t^2+176t+100) is -8t+176