What is the integral of 6x^{2/3} ?

The integral of 6x^{2/3} is 18/5 x^{5/3}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 6x^{2/3}

\int 6 x^{\frac{2}{3}} d x

\frac{18}{5} x^{\frac{5}{3}} + C

Solution steps

\int 6 x^{\frac{2}{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int x^{\frac{2}{3}} d x

Apply the Power Rule

: \frac{3}{5} x^{\frac{5}{3}}

= 6 \cdot \frac{3}{5} x^{\frac{5}{3}}

Simplify

6 \cdot \frac{3}{5} x^{\frac{5}{3}} : \frac{18}{5} x^{\frac{5}{3}}

= \frac{18}{5} x^{\frac{5}{3}}

Add a constant to the solution

= \frac{18}{5} x^{\frac{5}{3}} + C

(2 x + 5) (y^{2} + 4) d x - 4 y (x^{2} + 5 x + 6) d y = 0

\int e^{(a - s) x} d x

\int tan^{3} (8 x) sec (8 x) d x

\int \frac{10}{x ^{4}} d x

\int \frac{6 x ^{2} + 2 x - 1}{3 x ^{2}} d x