What is the integral of (1-cos^2(x))/(sin(x)) ?

The integral of (1-cos^2(x))/(sin(x)) is -cos(x)+C

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integral of (1-cos^2(x))/(sin(x))

\int \frac{1 - cos ^{2} ( x )}{sin ( x )} d x

- cos (x) + C

Solution steps

\int \frac{1 - cos ^{2} ( x )}{sin ( x )} d x

Rewrite using trig identities

= \int sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= - cos (x)

Add a constant to the solution

= - cos (x) + C

y^{^{'}} = 2 x + y

(3 y^{3} + 2 x y^{3}) + (3 x y^{2} + 3 y^{2}) (\frac{d y}{d x}) = 0

\frac{10}{ln ( x )}

16 - x^{2}, x^{2} - 2, - 3, 3

f (x) = lo g_{9} (x)

What is the integral of (1-cos^2(x))/(sin(x)) ?
The integral of (1-cos^2(x))/(sin(x)) is -cos(x)+C