What is the solution for (3y^3+2xy^3)+(3xy^2+3y^2)((dy)/(dx))=0 ?

The solution for (3y^3+2xy^3)+(3xy^2+3y^2)((dy)/(dx))=0 is y=e^{-1/3 (2(x+1)+ln(x+1))+c_{1}}

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(3y^3+2xy^3)+(3xy^2+3y^2)((dy)/(dx))=0

(3 y^{3} + 2 x y^{3}) + (3 x y^{2} + 3 y^{2}) (\frac{d y}{d x}) = 0

y = e^{- \frac{1}{3} (2 (x + 1) + l n (x + 1)) + c_{1}}

Solution steps

(3 y^{3} + 2 x y^{3}) + (3 x y^{2} + 3 y^{2}) (\frac{d y}{d x}) = 0

Solve separable ODE:

y = e^{- \frac{1}{3} (2 (x + 1) + l n (x + 1)) + c_{1}}

y = e^{- \frac{1}{3} (2 (x + 1) + l n (x + 1)) + c_{1}}

\frac{10}{ln ( x )}

16 - x^{2}, x^{2} - 2, - 3, 3

f (x) = lo g_{9} (x)

\frac{d}{d x} (\frac{4}{3} x^{3} - 4 x^{2} - 60 x + 10)

x^{\frac{1}{4}}, 2 - x, 0

What is the solution for (3y^3+2xy^3)+(3xy^2+3y^2)((dy)/(dx))=0 ?
The solution for (3y^3+2xy^3)+(3xy^2+3y^2)((dy)/(dx))=0 is y=e^{-1/3 (2(x+1)+ln(x+1))+c_{1}}