What is the derivative of 5sin(7x) ?

The derivative of 5sin(7x) is 35cos(7x)

What is the first derivative of 5sin(7x) ?

The first derivative of 5sin(7x) is 35cos(7x)

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\frac{d}{d x} (5 sin (7 x))

35 cos (7 x)

Solution steps

\frac{d}{d x} (5 sin (7 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (sin (7 x))

Apply the chain rule:

cos (7 x) \frac{d}{d x} (7 x)

= cos (7 x) \frac{d}{d x} (7 x)

\frac{d}{d x} (7 x) = 7

= 5 cos (7 x) \cdot 7

Simplify

= 35 cos (7 x)

\int (- y^{2} + 1) - (2 y^{2} - 2) d y

sec^{6} (x)

t \frac{d y}{d t} = t^{3} + 12 t^{3} y

\int x^{2} - x d x

x \to + 0 lim (9 x - 4)

What is the derivative of 5sin(7x) ?
The derivative of 5sin(7x) is 35cos(7x)
What is the first derivative of 5sin(7x) ?
The first derivative of 5sin(7x) is 35cos(7x)