What is the integral of x^2sec^2(x^3) ?

The integral of x^2sec^2(x^3) is 1/3 tan(x^3)+C

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integral of x^2sec^2(x^3)

\int x^{2} sec^{2} (x^{3}) d x

\frac{1}{3} tan (x^{3}) + C

Solution steps

\int x^{2} sec^{2} (x^{3}) d x

Apply u-substitution

: \int \frac{u sec ^{2} ( u ^{\frac{3}{2}} )}{2 x} d u

= \int \frac{sec ^{2} ( u )}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int sec^{2} (u) d u

Use the common integral:

\int sec^{2} (u) d u = tan (u)

= \frac{1}{3} tan (u)

Substitute back

u = x^{3}

= \frac{1}{3} tan (x^{3})

Add a constant to the solution

= \frac{1}{3} tan (x^{3}) + C

5 x e^{x} csc (x)

\int_{0}^{\infty} t \cdot e^{- s t} d t

\frac{d y}{d x}, y = x^{2} + 2

\int_{7}^{8} \frac{x}{x ^{2} + 4 x + 13} d x

\frac{1}{s} e^{- 2 s}

What is the integral of x^2sec^2(x^3) ?
The integral of x^2sec^2(x^3) is 1/3 tan(x^3)+C