What is (\partial)/(\partial x)(3x^4-sin(5x)+4x) ?

The answer to (\partial)/(\partial x)(3x^4-sin(5x)+4x) is 12x^3-cos(5x)*5+4

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(\partial)/(\partial x)(3x^4-sin(5x)+4x)

\frac{\partial}{\partial x} (3 x^{4} - sin (5 x) + 4 x)

12 x^{3} - cos (5 x) \cdot 5 + 4

Solution steps

\frac{\partial}{\partial x} (3 x^{4} - sin (5 x) + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{4}) - \frac{\partial}{\partial x} (sin (5 x)) + \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (3 x^{4}) = 12 x^{3}

\frac{\partial}{\partial x} (sin (5 x)) = cos (5 x) \cdot 5

\frac{\partial}{\partial x} (4 x) = 4

= 12 x^{3} - cos (5 x) \cdot 5 + 4

x \to - 2 lim (x + 2)

(y - x) y^{^{'}} = y - x + 8

x \to 0 lim (2 x + 1 - 1)

\frac{d}{d x} ((ln (3 x))^{5})

2 x^{2} - 7 x + k

What is (\partial)/(\partial x)(3x^4-sin(5x)+4x) ?
The answer to (\partial)/(\partial x)(3x^4-sin(5x)+4x) is 12x^3-cos(5x)*5+4